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cpp array length

f you mean a C-style array, then you can do something like:

int a[7];
std::cout << "Length of array = " << (sizeof(a)/sizeof(*a)) << std::endl;
This doesn't work on pointers, though, i.e. it won't work for either of the following:

int *p = new int[7];
std::cout << "Length of array = " << (sizeof(p)/sizeof(*p)) << std::endl;

void func(int *p)
    std::cout << "Length of array = " << (sizeof(p)/sizeof(*p)) << std::endl;

int a[7];
In C++, if you want this kind of behaviour, then you should be using a container class; probably std::vector.


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